-6y^2-12y+18=0

Solution for -6y^2-12y+18=0 equation:

-6y^2-12y+18=0

a = -6; b = -12; c = +18;
Δ = b2-4ac
Δ = -122-4·(-6)·18
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-24}{2*-6}=\frac{-12}{-12}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+24}{2*-6}=\frac{36}{-12}
=-3
$